Exercise 1: Determining the Concentration of Acetic Acid
11th grade CHEMISTRY TITRATION LAB! I have a tritation lab due tomorrow and i am stumped on a couple things. Its a titration lab using sodium hydroxide (NaOH)- 250 mL 0.300 M concentration, 10 mL of an unknown substance of vinegar, the avg. Of titrated NaOH in the flask with vinegar is 27.7 mL.
Data Table 1. NaOH Titration Volume.
Initial NaOH Volume (mL) | Final NaOH Volume (mL) | Total volume of NaOH used (mL) | |
Trial 1 | 9 | .5 | 8.5 |
Trial 2 | 9 | .25 | 8.25 |
Trial 3 | 9 | 0 | 9 |
Average Volume of NaOH Used (mL) : 8.58 |
Data Table 2. Concentration ofCH3COOH in Vinegar.
Average volume of NaOH used (mL) | Concentration CH3COOH in vinegar(mol/L) | % CH3COOH in vinegar |
* I don't know if I am doing it correctly, and end up with crazynumbers. Can someone PLEASE break it down easily for me?
Question
The manufacturer of the vinegar used in the experiment statedthat the vinegar contained 5.0% acetic acid. What is the percenterror between your result and the manufacturer’s statement?
UPDATE: NaOH is 0.5M
I DO NOT know CH3COOH.... It was for me to find outin that chart.....
UPDATE AGAIN: I know he acedic acid was not given. That wassuppose to be what I am figuring out. This is what it says fordata:
UPDATE AGAIN: I DO NOT KNOW THE VOLUME BECAUSE THAT IS WHAT ISIN THE BLANKS THAT I NEED TO FIGURE OUT!!!!!!!!!!!